Chemistry, asked by heavenstutorial09, 1 month ago

A body of mass 70 kg travels with a speed of 15 km/hour. Calculate the de-Broglie wavelength of
the body

Ans. 2.27 x 10 ^-34..

Answers

Answered by himanshubainiwal68
2

Answer:

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Answered by talasilavijaya
2

Answer:

The wavelength of the body is 2.27\times 10^{-36}m

Explanation:

Debroglie wavelength:

  • The wavelength (λ) associated with a particle in relation to its momentum and mass is known as deBroglie wavelength.
  • The de Broglie wavelength is given by

         \lambda=\dfrac{h}{p}=\dfrac{h}{mv}

        where p = mv is the momentum of the particle, m is the relativistic mass, v is the velocity and h is the Planck's constant, 6.62 \times 10^{-34} m^2 kg / s.

Given the mass of a body, m = 70kg

Speed of the body,    

v=15 \dfrac{km}{hour}=15\times  \dfrac{5}{18} \dfrac{m}{s}

Substituting the given values in the above formula,

\lambda=\dfrac{h}{mv}=\dfrac{6.62 \times 10^{-34}}{70\times 15\times  \dfrac{5}{18}}

             =\dfrac{6.62 \times 10^{-34}}{291.67}

             =0.0227\times 10^{-34}=2.27\times 10^{-36}m

Therefore, the wavelength of the body is 2.27\times 10^{-36}m.

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