Physics, asked by Shabibs, 1 year ago

A body of mass 70 kg when completely immersed in water displaces 20000cm^3of water. Find the mass of body in water

Answers

Answered by Anonymous
3
Density of the body =
 \frac{mass \: of \: body}{volume \: of \: water \: displaced \: by \: it}  \\  \frac{70 \times 1000g}{20000}  =  \frac{70}{2}   = 35 \: g \: per \:  {cm}^{3}
Mass of body in water = 35+70000 = 70035 g = 70.035 kg .

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Shabibs: Sorry wrong answers
Answered by Anonymous
3
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➧ Volume = 2000 cm³

➾ 2000 x 10-⁶ m³

➾ 2 x 10³ x 10-⁶ m³

➾ 2 x 10-³ m³

➧ So, density of the substance
➾ 70 kg/ 2 x 10-³ m³

➾ 35 x 10³ kg/m³

➧ Relative density =  density of substance / density of water

➾ 35 x 10³ / 10³
➾ 35 ...✔

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