A body of mass 8 kg is moved by a force F = 3x
N, where x is the distance covered. Initial position
is x = 2 m and the final position is x= 10 m. The
initial speed is 0.0 m/s. The final speed is
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The final speed is 6m/s.
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Answer:
48 m/s
Explanation:
x=10-2=8m
So F=3×8=24 N
F=ma
Then a=3 m/s^2
Now ,
Final speed, v = 2×3×8
= 48 m/s
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