Question

A body of mass 8 kg moving towards right at a speed of 3 m/s, strikes a body of mass 1 kg,

which is moving towards left at a speed of 10 m/s. If the final velocity of 1 kg body after

impact is 4 m/s towards right. Calculate the coefficient of restitution and the final velocity of 8

kg body after impact.​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

Correct option is

A

30J

Momentum will be conserve.

So, mv=(m

1

+m

2

)u

10×3=(10+5)×V

V is a velocity of the composite mass

On solving, we get

30=15×V

V=2m/s

So, KE=

2

1

mv

2

=

2

1

×(10+5)(2)

2

=

2

1

×15×4=30kg−m

2

/sec

2

KE=30kg−m

2

/sec

2

Explanation:

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