Question

A body of mass 8 kg travels distances of 4,5 and 6m respectively in successive seconds. Then the force acting on it is:

Answer 1

Mass(m)=8kg (given)

As we already know, F=ma

so , we need to find its acceleration.

a=v-u/t

or

a= v/t (where v is only velocity)

v=s/t

=> v = 4/1. (because given successive seconds)

next sec. => v= 5/1 and so on.....

a= v/t

=> a = v-u / t

=> a = 5-4 / 1

Therefore, a=1 m/s²

So, Force acting on the body is = ma

= 8×1= 1 N .

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