Question

A body of mass 8kg is moved by a force F =3x. where x is the distance covered.Initial position is x=2m and final position is x= 10m.if final speed is 0.0m/s what is the final speed​

Answer 1

Answer:

F=3x=ma

3x=8a

a=3x/8

dv=adx

(integration)dv=(integration)adx

(integration)dv=(integration)(3x/8)dx

v(final)-v(initial)=(3/8)(x^2/2)=3x^2/16(from x=2 to x=10)

v(final)-0=(3/16)(10^2-2^2)

=(3/16)(100-4)=(3/16)*96

v(final)=18m/s(Answer)