A body of mass 8kg moving with a velocity of 20m/s collides head on with another body of mass 5kg moving with velocity of 10m/s. If the collision is perfectly inelastic, calculate the velocity of the first body after collision and the loss of K.E. during collision.
Answers
Answer:
ANSWER
Given : m1=2kg m2=1kg u1=3 m/s u2=4 m/s
Let the common velocity of the combined body be V
Mass of combined body M=2+1=3kg
Applying conservation of momentum :
2×3−1×4=3×V ⟹V=32 m/s
Momentum of the system P=2×3−1×4=2 kg m/s
Loss in kinetic energy of the system due to collision ΔK.E=K.Ei−K.Ef
ΔK.E=21(2)×32+21(1)×42−21(3)×(32)2
⟹ΔK.E=349 J
Answer:
Given : m
1
=2kg m
2
=1kg u
1
=3 m/s u
2
=4 m/s
Let the common velocity of the combined body be V
Mass of combined body M=2+1=3kg
Applying conservation of momentum :
2×3−1×4=3×V ⟹V=
3
2
m/s
Momentum of the system P=2×3−1×4=2 kg m/s
Loss in kinetic energy of the system due to collision ΔK.E=K.E
i
−K.E
f
ΔK.E=
2
1
(2)×3
2
+
2
1
(1)×4
2
−
2
1
(3)×(
3
2
)
2
⟹ΔK.E=
3
49
J