Question

a body of mass a 3 kg and body B of mass 10 kg are dropped from a height of 9 m. calculate the momentum their potential energy and kinetic energy when they are 10 metre above the ground​

Answer 1

Answer:

Explanation:

Velocity when they're 10 m above the ground (i.e after travelling 14.9 m - 10 m = 4.9 m) is

v = sqrt(2gS) (since u = 0)

= sqrt(2 × 9.8 m/s² × 4.9 m)

= 9.8 m/s

Momentum

p1 = m1v = 3 kg × 9.8 m/s = 29.4 kg m/s

p2 = m2v = 10 kg × 9.8 m/s = 98 kg m/s

Potential energy

U1 = m1gh = 3 kg × 9.8 m/s² × 10 m = 294 J

U2 = m2gh = 10 kg × 9.8 m/s² × 10 m = 980 J

Kinetic energy

K1 = 0.5m1v² = 0.5 × 3 kg × (9.8 m/s)² = 144.06 J

K2 = 0.5m2v² = 0.5 × 10 kg × (9.8 m/s)² = 480.2 JPls mark me the brainliest