A body of mass m=4kgm=4kg starts moving with velocity v0v0 in a straight line is such a way that on the body work is being done at the rate which is proportional to the square of velocity as given by P=βv2P=βv2 where β=0.6932.β=0.6932. Find the time elapsed in seconds before velocity of body is doubled.
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It's an integer answer b/w 0 to 9. sry that's all I know
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