Question

a body of mass M 5 kg moves along the x-axis with a velocity 2 metre per second the second body of mass 10 kg moves along the y axis with a velocity of root 3 M per second day collide at the origin and stick together if the moment amount of heat liberated in the collision is Lambda by 3 then find Lambda​

Answer 1

This is a question on momentum.

Momentum = mass × Velocity.

By law of conservation of linear momentum :

Initial momentum = Final momentum.

a) Let the final velocity be V.

Initial momentum equals :

Root 3 m/s = 1.73 m/s

5 × 2 + 10 × 1.73 = 27.3 kgm/s

Final momentum :

(10 + 5) V = 15 V

Equating the two to get V:

15 V = 27.3

V = 1.82 m/s

b) KE = 1/2mv^2

Mass = 15kg

V = 1.82 m/s

Heat energy = Kinetic energy

= 1.82 × 1.82 × 15 × 0.5 = 24.843 Joules