Question

A body of mass m accelerates uniformly from rest to s speed vf in time tf. Show that the work done on the body as a function of time 't'. in terms of vf and tf is​

Answer 1

Answer: work = m/2*(vf/tf)^2

Explanation:

work done = F * r * costheta here theta = 0 degrees

work = F * r

now F = ma = m(change in velocity)/time = m$v_{f}$/$t_{f}$

and r = 1/2at^2 = 1/2 (vf/tf)^2

work = m/2*(vf/tf)^2 answer