A body of mass M at rest explores into three masses two of which having mass M/4 flown over in perpendicular directions with velocity 3 m/s and 4 m/s respectively. The third piece will be flown off with a velocity
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A body of mass m at rest explodes into 3 partrs, having masses in ratio 1:1:3. If two parts having equal masses move at right angles to each other with 10 m/s each , the velocity of third will be
(a)2–√m/s(b)52–√m/s(c)5m/s(d)102–√m/s(a)2m/s(b)52m/s(c)5m/s(d)102m/s
jeemain physics class11 unit4work-power-energy q47 medium
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asked Jul 22, 2013 by meena.p
retagged Jul 10, 2014

1 Answer
Let the mass of each part be m5,m5,3m5m5,m5,3m5
Momentum of each part flying at right angle will be same and at 45∘45∘ with the third part.

m5m5×15cos45+m5×15cos45+m5×15cos45=3m5×15cos45=3m5vv
152–√+152–√152+152=3v=3v
v=102–√v=102
=52–√m/s=52m/s
Hence b is the correct answer.
A body of mass m at rest explodes into 3 partrs, having masses in ratio 1:1:3. If two parts having equal masses move at right angles to each other with 10 m/s each , the velocity of third will be
(a)2–√m/s(b)52–√m/s(c)5m/s(d)102–√m/s(a)2m/s(b)52m/s(c)5m/s(d)102m/s
jeemain physics class11 unit4work-power-energy q47 medium
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asked Jul 22, 2013 by meena.p
retagged Jul 10, 2014

1 Answer
Let the mass of each part be m5,m5,3m5m5,m5,3m5
Momentum of each part flying at right angle will be same and at 45∘45∘ with the third part.

m5m5×15cos45+m5×15cos45+m5×15cos45=3m5×15cos45=3m5vv
152–√+152–√152+152=3v=3v
v=102–√v=102
=52–√m/s=52m/s
Hence b is the correct answer.
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