Physics, asked by niharikasapra, 1 year ago

A body of mass M at rest explores into three masses two of which having mass M/4 flown over in perpendicular directions with velocity 3 m/s and 4 m/s respectively. The third piece will be flown off with a velocity

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Answered by Ramta
1
Energy

A body of mass m at rest explodes into 3 partrs, having masses in ratio 1:1:3. If two parts having equal masses move at right angles to each other with 10 m/s each , the velocity of third will be

(a)2–√m/s(b)52–√m/s(c)5m/s(d)102–√m/s(a)2m/s(b)52m/s(c)5m/s(d)102m/s

jeemain physics class11 unit4work-power-energy q47 medium

  

 

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asked Jul 22, 2013 by meena.p 
retagged Jul 10, 2014



1 Answer

Let the mass of each part be m5,m5,3m5m5,m5,3m5

Momentum of each part flying at right angle will be same and at 45∘45∘ with the third part.



m5m5×15cos45+m5×15cos⁡45+m5×15cos45=3m5×15cos⁡45=3m5vv

152–√+152–√152+152=3v=3v

v=102–√v=102

=52–√m/s=52m/s

Hence b is the correct answer.

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