Physics, asked by Laiba2003, 1 month ago

a body of mass M attached to the spring performs SHM its time period in terms of extension X produces in the spring will be​

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Answered by 333tanyasharma
0

Explanation:

T=2π√L/g. where L=length of string and g=acceleration due to gravity

After attaching the body to the string extension produced in the string= Length of the string =x

so, L=x

T=2π√x/g

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