Physics, asked by Rasha4188, 8 months ago

A body of mass m falls from a height h onto a pan (of
negligible mass) of a spring balance as shown. The spring
also possesses negligible mass and has spring constant k.
Just after striking the pan, the body starts socillatory motion
in vertical directioin of amplitude A and energy E. Then
(a) A = mg/k
(b) A = mg/k √1 + 2kh/mg
(c) E = mgh + 1/2 kA²
(d) E = mgh + (2mg/2k)²

Answers

Answered by naTEA
0

A body of mass m falls from a height h onto a pan (of

negligible mass) of a spring balance as shown. The spring

also possesses negligible mass and has spring constant k.

Just after striking the pan, the body starts socillatory motion

in vertical directioin of amplitude A and energy E. Then

(a) A = mg/k

(b) A = mg/k √1 + 2kh/mg

(c) E = mgh + 1/2 kA²

(d) E = mgh + (2mg/2k)²

answetvzizjidjd

Answered by hariommaurya97
2

hope it helps u

this is full solution

Attachments:
Similar questions