a body of mass M has a velocity V if the mass of the body increases 49 times but the kinetic energy remains same how does the velocity of the body changes
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Answer:
Given: Initial velocity =v; Final velocity =3v
Initial kinetic energy k1=21×m×v2
Final kinetic energy k2=21×m×(3v)2=91×21mv2
Change in kinetic energy =21mv2−91×21mv2
=21mv2(1−91)
=98×21×mv2
=98× Initial kinetic energy.
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