Question

a body of mass m hits normally a rigidwall with velocity v/2 and bounces back wiyh the same velocity.the impulse expesrienced by the body​

Answer 1

Answer:

impulse = change in momentum

I= m *v/2  -(-m*v/2)

I=2 m v/2

I=m v

hope gonna help you

Answer 2

Answer:

mv is your answer mate ok