Question

 A body of mass m in moving with a velocity v. What is the final KE, if its velocity is doubled?​

Answer 1

Answer:

$kinetic \: energy \: = \frac{m {v}^{2} }{2}$

so ,

when

${v}^{'} = 2v$

${k.e.}^{'} = \frac{ {4m {v}^{2} }}{2}$

so ,

$k.e. = 2m {v}^{2}$