Question

A body of mass m is displaced from point A(3,1,2) to point B(4,3,3) under the effect of a force F= (3i^ + 2j^+ 4k^) calculate work done by the force

Answer 1

workdone is the dot product of force and displacement.

i.e., $W=\vec{F}.\vec{\Delta x}$

here it is given that, force acting on a body of mass m, $\vec{F}$ = 3i + 2j + 4k

under the effect of force F, body displaces from point A(3,1,2) to point B(4,3,3).

so, displacement, $\vec{\Delta x}$ = B - A = (4 - 3)i + (3 - 1)j + (3 - 2)k

= i + 2j + k

so workdone , W = $\vec{F}.\vec{\Delta x}$

= (3i + 2j + 4k).(i + 2j + k)

= 3 × 1 + 2 × 2 + 4 × 1

= 3 + 4 + 4

= 11 J

Answer 2

Answer:

Here is the answer ... this is done in short .. so that can be easily understood