Question

A body of mass m is dropped from a height h on to a
spring of force constant K. The maximum compression
in the spring is x, then
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Answer 1

Answer: 

mg(h+x)=12kx2mg(h+x)=12kx2

The loss in potential energy of the mass =elastic potential energy stored in spring .

Let x be compression in spring

The mass falls through height (h+x)

⇒mg(h+x)=12kx2

Hope this helps you!!

Answer 2

Answer:

hii mate

Explanation:

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