Physics, asked by jahnvisingh445, 1 year ago

A body of mass m is dropped from height h above the ground. Calculate the velocity v of the body when it has lost half its potential energy

Answers

Answered by sourya1794

23

Explanation:

lost of potential energy will be equal to gain in kinetic energy

when it drops from a hight of h

its velocity at ground is =(2gh)^1/2

gain in kinetic energy = 1/2Mv^2

= Mgh

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