a body of mass M is dropped from the top of the tower during the first second of the motion it will fall through
Answers
Answered by
4
Answer:
body will fall through 5 m in 1 sec
Explanation:
a body of mass M is dropped from the top of the tower during the first second of the motion it will fall through
body is dropped so initial velocity u = 0 m/s
time = 1 sec
a = g = 10 m/s²
S = distance fall through
S = ut + (1/2)at²
=> S = 0*1 + (1/2)(10)* 1²
=> S = 0 + 5
=> S = 5
body will fall through 5 m in 1 sec
Answered by
3
Answer:
4.9m
Explanation:
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