Question

A body of mass m is moving along +X-axis under the
force F = -kx. While crossing the origin its velocity is v.
Find the value of x when particle comes to rest.​

Answer 1

Answer:

ANSWER

Given that F=i-2j, we can say that the acceleration will be a=0.5i-j since a=

m

F

and mass is given to be 2kg in this question. After this, we calculate the velocity after breaking initial velocity V=3i+4j into its components. Thus, in the x-direction, Vx=u(x)+a(x)×t=3+(0.5×4)=5 m/s.

In the y direction,V y=u ( y )+to ( and )×t=4−4=0

Therefore we get answer C, which is 5 m/s in the x direction.

Explanation:

Thank you