Question

a body of mass m is moving with a velocity 5ms-1 . it's kinetic energy is 25 j. if it's velocity is doubled, what is it's kinetic energy?​

Answer 1

Answer:

kinetic energy quadruples

Answer 2

Answer:

$kinetic \: energy = \frac{1}{2}m {v}^{2} \\ \frac{1}{2} \times m \times (5 \frac{m}{s}^{2} ) = 25joule \\ \frac{1}{2} \times m \times 25 \frac{m}{s} = 25joule \\ m \times \frac{25}{2} \frac{m}{s} = 25joule \\ m = 25 \times \frac{2}{25} \frac{m}{s} \\ m = 2kg \\ the \: mass \: is \: 2kg.$

Double velocity= 5m/s×2= 10m/s

Kinetic energy= 1/2mv^(2)

1/2×2kg×(10m/s)^(2)

1/2×2kg×100m/s= 200/2= 100J

It is the answer.