Question

A body of mass m is projected at an angle a
45 from horizontal calculate the change
in momentes from its departures and a arrival
position in a vertical direction, neglect air
resistance​

Answer 1

Velocity during projection=u i

Velocity component along y axis=usin45

=u/√2 j

After reaching the ground, velocity in y axis is -u/√2 j

So, change in momentum along vertical direction or y axis=m2v2-m1v1=-√2mu

Answer 2

Explanation:

Change in momentum =mvsinθ−(−mvsinθ)

=2mvsinθ

Given, θ=

4

π

Change in momentum =

2

mv