Question

A body of mass m is projected at an angle a to the horizontal, the projectile at highest point breaks into two fragments of equal masses.One of the fragments retraces its path of projection.The velocity of other fragment just after explosion is

Answer 1

Answer:

let the velocity of the particle before explosion be v

so at highest position the velocity of particle will v cos a

the case is something as shown above in the picture:-

as one particle retraces the path so

v2= v cos a

so conservation of momentum:-

m X v cos a= m/2 X v2 - m/2 X v cos a

3/2 X m X v cos a=m/2 X v2

so

by the solving the equation:-

v2=3 v cos a