Question

A body of mass m is projected with a velocity u making an angle θ with horizontal. Its horizontal range is R. The body splits into two equal parts at the highest point. If one retraces its path then range of other particles is

Answer 1

Answer:

At highest point horizontal velocity of particle before splitting =ucosθ

using linear momentum conservation

mucosθ=

2

m

v+

2

m

(0)

⇒v=2ucosθ

Since the horizontal component =2 times the initial velocity so range will also become twice since time depends only on vertical component of velocity

⇒ distance travelled =

2

R

+R=

2

3R