Question

A body of mass m is projected with speed u making an angle with horizontal.the power delivered by gravity to it at half of maximum height from ground will be

Answer 1

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~* THE ANSWER OF YOUR QUESTION IS..*~

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THE HORIZONTAL COMPONENT OF ITS VELOCITY REMAINS CONSTANT .
ITS VERTICAL COMPONENT CHANGES WITH ALTITUDE AS FOLLOW


V^2=U^2SIN^2THETA - 2gH/2

FROM THIS CALCULATION CALCULATE V

THEN P=F * V

P= -Mg*VERTICAL COMPONENT OF VELOCITY

YOU WILL GET INSTABTANEOUS POWER AS

P(H/2)=Mg / root 2 sin theta


HOPE IT WILL HELP YOU