Physics, asked by vaisya24, 3 months ago

A body of mass m is raised to heighth from
ground along three different paths viz l, ll and
against gravity as shown below. If W, W, and W,
are the work done along the respective paths of
II and III, then the correct option is there is no non
conservative force)
[NCERT Pg. 124
Path III
Path 11
h
Path 1​

Answers

Answered by akg900930
7

Answer:

Since the gravitational field is a conservative field, hence the work done in taking a particle from one point to another in a gravitational field of path independent.

⟹ w

1

=w

2

=w

3

Answered by kjuli1766
13

Concept:

The influence that a large body has on the area around it, exerting a force on another large body, is described by a gravitational field.

When work is performed on a body, the body's energy level increases because work transmits energy to the body.

Given:

A body is raised to a height from the ground along three different paths I, II, and III against gravity. The work done along the respective path is W₁, W₂, and W₃.

Find:

The comparison of the work done along the paths.

Solution:

The work involved in moving a particle from one location to another in a gravitational field of route independence results from the gravitational field's conservatism.

A conservative force field is a gravitational field. Work performed in a conservative force field is route independent.

Therefore,

W₁ = W₂ = W₃

The work done along the three paths I, II, and III is equal.

#SPJ3

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