Physics, asked by JassiK0001, 10 months ago

A body of mass m is situated in a potential field U(x) = U0(1-cos αx ) when U0 and α are constants. Find the time period of small oscillations​

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Answered by Anonymous
0

The time period of small oscillations can be represented as :

  • As per the question, U(x) = U₀(1-cos αx )
  • Differentiating both sides by d(x):

F= \frac{-dU}{dx}=\frac{-d(U0-U0cos ax )}{dx}

= -U₀αsinαx

= -U₀ααx ( for small αx , sinαx ≈ αx)

= -U₀α²x

  • As we know , F = -kx
  • so, k= U₀α²
  • Therefore, Time period (T) = 2\pi \sqrt{\frac{m}{Uo a^{2} } }
Answered by Anonymous
1

Answer:

hiii

mera sst ka paper bhaut accha gya.....☺️

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