Question

A body of mass m is suspended by two strings making Angles $\alpha$ & $\beta$ with the horizontal as shown , Find tension in the string ..

★ Plz ${\huge{Don't}}$ Answer ​

Answer 1

it will help you dear...

Answer 2

${\huge{\underline{\underline{\mathrm{Answer}}}}}$

First Step -

⠀ ⠀⠀⠀☆ $\bf{Draw \: FBD}$

$\bf{refer \: to \: the \: attachment}$

Now ,

$\bf{as \: the \: body \: is \: in \: equilibrium \: }$

$\bf{the \: various \: forces \: must \: add \: to \: zero}$

Taking Horizontal Component -

$\pink {\colon \longrightarrow} \: t_{1} \cos( \alpha ) = t_{2} \cos( \beta ) \\ \\ \green{ \implies} t_{2} = t_{1} \frac{ \cos( \alpha ) }{ \cos( \beta ) }$

Taking Vertical Component -

$\pink{ \colon \longrightarrow} t_{1} \sin( \alpha ) + t_{2} \sin( \beta ) = mg$

Now , refer to the second attachment !

So , here we are , We've got the answer !!