Question

a body of mass M is thrown vertically upward with velocity v and another body whose mass is twice that of a is thrown upward with a velocity 2v what is the maximum height reached by b

Answer 1

Given:

Mass of body A = M

Velocity of body A = v

Mass of body B = 2M

Velocity of body B = 2v

To find:

Maximum height reached by B

Solution:

At the highest point all the kinetic energy will be converted into potential energy:

1/2mv² = mgh

where m = mass of the body

g is the acceleration due to gravity

h is the maximum height achieved

v is the velocity of the body

For body B:

1/2(2M)(2v)² = (2M)gh

4v² = 2Mgh

h = 2v²/ Mg

Therefore the maximum height achieved by body B = 2v²/ Mg.