A body of mass m kg initially at redt attains a velocity v m/sec i time t under the actin of contant force f .the power supplied to the mass at studyaa .com
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m = mass of the body
F = force on the body
a = acceleration of the body
acceleration of the body is given as
a = F/m eq-1
v₀ = initial velocity = 0 m/s
v = final velocity
t = time of travel
using the equation
v = v₀ + a t
using eq-1
v = 0 + (F/m) t
v = Ft/m eq-2
kinetic energy gained is given as
KE = (0.5) m v²
KE = (0.5) m (Ft/m)²
KE = (0.5) (F²t²/m)
power is given as
P = work done / time
here work done is the kinetic energy gained
so P = KE/t
P = ((0.5) (F²t²/m))/t
P = ((0.5) (F²t/m)
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