Question

A body of mass M kg (where M is the last two digits of your student ID except invalid 0) is suspended by a spring, which stretches 0.1 m when the body is attached. It is then displaced downward an additional 0.05m and released. calculate (1) the amplitude and(2) period of the resulting simple harmonic motion?​

Answer 1

Answer:

Let the two numbers be x and y.

As per condition 1, i.e., Two numbers are in the ratio 3 : 4.

The equation becomes,

yx=43

∴4x−3y=0  

Step-by-step explanation:

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Answer 2

Answer:

like this you have to do fo your question ok