Physics, asked by krishna07, 1 year ago

A body of mass m , moves in a circular path of radius r under certain centripetal force = k/r² , where k is constant . the kinetic energy of particle is ?

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Answered by qais
2
centripetal force=( m×v²)/r
(m×v)/r²=k/r²
 kinetic energy= 1/2 m×v²
solving both equation 
kinetic energy= k/2r , where r is radius

krishna07: thanks dude ! u which collage
qais: BISSS bokaro
Answered by mohnishkrishna05
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