Science, asked by owaisrafi074, 11 months ago

a body of mass m moves with velocity v and collides inelastically with another identical mass.after collision the 1st mass moves with v/√3in a direction perpendicular to initial direction find speed of second mass after collision

Answers

Answered by sparshraghav123

Explanation:

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${\fbox{\underline{\red{Answer= 2/root3}}}}$

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Attachments:

Answered by ManuAgrawal01

GIVEN:-

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$\: \rm{a \: body \: of \: mass \: m \: moves \: with \: velocity \: v \: and \: collides }$

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$\rm{1st \: mass \: moves \: with \: \frac{2v}{ \sqrt{3} } \: in \: a \: direction }$

TO FIND:-

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The second speed of mass after collision

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FORMULAE USED:-

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• ${\boxed{\rm{\blue{Concentration \: of \: Momentum}}}}$

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SOLUTION:-

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Let after collision 2nd mass moves at angle ∅. The horizontal momentum of the 2nd mass = mv ' cos∅

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According to conservation of momentum

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mv = mv ' cos∅

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v = v ' cos∅------------(1)

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The vertical momentum of the 2nd mass = mv ' sin∅

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According to conservation of momentum

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$\bf\longrightarrow \frac{mv}{ \sqrt{3} } + mv \: ' sin∅ = 0$

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$\bf\longrightarrow \frac{v}{ \sqrt{3} } = - v \: ' sin∅ - - - - - 2$

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Equation (1)² + (2)²

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$\bf\longrightarrow {v}^{2} + \frac{ {v}^{2} }{3} = {v}^{2}$

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$\bf\longrightarrow {v}^{2} = \frac{4 {v}^{2} }{3}$

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$\bf\longrightarrow {v}^{'} = \frac{2v}{ \sqrt{3} }$