A body of mass m, moving with a velocity u1 undergoes a heat on perfectly inelastic collision with a body of mass m2 initially at rest. Show that the ratio of final k.e and initial ke, of the system is m1/m1 + m2.
Answers
Answer:
Using momentum conservation and equation for coefficient of restitution in case of elastic collision, we get,
v
1
=
m
1
+m
2
m
1
−m
2
uandv
2
=
m
1
+m
2
2m
1
u
where u is the velocity of m
1
and m
2
is at rest.
Kinetic energy of m
1
=1/2×m
1
v
1
2
Therefore, fraction of energy retained =(
m
1
+m
2
m
1
−m
2
)
2
Kinetic energy of m
2
=1/2×m
2
v
2
2
Therefore, fraction of energy transferred =
(m
1
+m
2
)
2
4m
1
m
2
.
Also when both the masses are equal, the velocity gets interchanged. Therefore, 100% energy is transferred. No energy is lost in elastic collisions.
Hope it helps...
Thanks
Regards
Teeva Aryan Das
Answer:
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