Question

a body of mass m moving with velocity u collides head on elastically with another body of mass 2m at rest .the ratio of kinetic energy before and after collision is ..I will mark as brainliest...​

Answer 1

Explanation:

KE

before

=

2

1

mv

1

2

2

1

mv

2

=

V

1

2

V

2

Since V

1

=

m

1

+m

2

m

1

−m

2

V

1

=

m+2m

m−2m

V=−

3

V

Hence ratio of KE=

V

1

2

V

2

=9:1