Question

A body of mass m slides down a rough inclined plane (miu =1/2) .if it would have been a fractionless surface , force acting on the body is​

Answer 1

Answer:

5m

Explanation:

Force acting on the body mking down th plane is F=mgsin(theta)

Here the value of sin(theta) is given to be 1/2

Hence, F=mgsin(theta)

=m(10)(1/2)

=5m