Question

A body of mass 'm', suspended from a spring with force constant k,
vibrates with 'f1'. When its length is cut into half and the same body is
suspended from one of the halves, the frequency is 'f2. Find out f1byf2
​

Answer 1

Answer:

• f1 is f = 2π√l/g
• d2 is f =
• $2\pi \sqrt{ \frac{ \frac{l}{2} }{g} }$