A body of mass 'm', suspended from a spring with force constant k,
vibrates with 'fi'. When its length is cut into half and the same body is
suspended from one of the halves, the frequency is 'fz'. Find out fifz'
(fis,'= 0.707)
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B
f/2
Given,
Time period of SHM is one spring and mass is connected
Spring constant, k
Attached mass, m
So, frequency is, f=2πmk
As in the figure, if another spring is added in parallel.
Both spring identical, new spring constant for two parallel spring.
knew=k+k=2k
Time period of oscillation,
fnew=2πknewm=2π2km
fnew=212πkm=2f
Hence, new frequency is 2f
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