Question

A body of mass m1 collides elastically with another mass m2 at rest. There is maximum transfer of energy when

Answer 1

Explanation:

With according to the “conservation of momentum”,

Before the collision mass of body = $m_{1}$

After the collision mass of body = $m_{2}$

The collision is elastic therefore, it conserved momentum and kinetic energy.

So, the body has initial velocity and final velocity which are before and after the collision of the body respectively.

$v_{1}=\frac{m_{1}-m_{2}}{m_{1}+m_{2}} u_{1}$

$v_{1}=\frac{3}{4} u_{1}$

$\frac{3}{4} u_{1}=\frac{m_{1}-m_{2}}{m_{1}+m_{2}} u_{1}$

$3 m_{1}+3 m_{2}=4 m_{1}-4 m_{2}$

$7 m_{2}=m_{1}$

$\frac{m_{1}}{m_{2}}=\frac{1}{7}$

Hence, the ratio of the mass of the body before and after the collision of the respective body is 1:7 respectively.

Answer 2

Answer:

when m1=m2 There is maximum transfer of energy