Question

A body of mass M1 collides head on elastically with a stationary body of mass m2 if velocities of m1 before and after the collision are V and -v/3 respectively then the value of m1 by M2

Answer 1

Answer:

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Explanation:

Let velocity of body A is u and velocity of body B is v.

Body collides elastically.

⇒m1u=−m14u+m2v ...1

Divide equation 1 by u, ⇒m1=−4m1+m2uv ⇒45m1=m2uv

⇒m2m1=54×uv ...2

Coefficient of restitution (e=1)=−u−4u−v ⇒uv=43

Put the value of uv in equation 2, we get m2m1=53

Answer 2

Answer:

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