Question

A body of mass m1 moving with the velocity 3 metre per second collides with another body at rest of mass m2 after collision the velocities of two bodies are 2 metre per second and 5 metre per second respectively along the direction of the motion m2 the ratio of m1 is to m2 is

Answer 1

Answer:

5:1

Explanation:

P = M × V

P1 + P2 = P1' + P2'

m1(3) + m2(0) = m1(2) + m2(5)

3m1 - 2m1 = 5m2

m1 = 5m2

m1/ m2 = 5

m1 : m2 = 5 : 1

Answer 2

The ratio of m₁ and m₂ is 5:1.

Explanation:

Given that,

Velocity of first body = 3 m/s

Velocity of third body = 2 m/s

Velocity of fourth body = 5 m/s

Second body at rest.

We need to calculate the ratio of m₁ and m₂

Using conservation of momentum

$m_{1}u_{1}+m_{2}u_{2}=m_{1}\times2+m_{2}\times5$

Put the value into the formula

$m\times3+0=m_{1}\times2+m_{2}\times5$

$3m_{1}=2m_{1}+5m_{2}$

$\dfrac{m_{1}}{m_{2}}=\dfrac{5}{1}$

Hence, The ratio of m₁ and m₂ is 5:1.

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Topic : momentum

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