Question

a body of mass m1 of a substance of specific heat capacity c1 at a temp. t1 is mixed with another body of mass m2 of specific heat capacity c2 at a lower temperature t2 . deduce an expression for the temp. of the mixture t3

Answer 1

Hey...Rajdeep here!

By principle of method of mixtures,
Assuming that no heat is lost,
Heat lost by hot body = Heat gained by cold body.

Given, Heat lost by hot body is m1 x c1 x (t1-t3)
(because it is at higher temperature)

And Heat gained by cold body is m2 x c2 x (t3-t2)

Now,
m1 x c1 x (t1-t3) = m2 x c2 x (t3-t2)
Hope this helps.....