a body of mass moving hundred gram moving on a test track has final kinetic energy of fifty joule after traveling a distance of ten centimeter. assuming ninety percent loss of energy due to friction initial speed of the body is
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Explanation:
1/2mv2 = 50J
Ki × 10/100 = 50
to find Ki
hear, Ii = me2 m = 100/1000kg.
so,
1/2mv2 = 50J
theirfore,
Ki = 500J ( Ki×10/100=50)
1/2mv2 = 500
thus,
u = root of (2×500/100)/1000
》2×5/1000
》1/100
》10ms-1
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A body of a mass 2kg moving on a smooth track has kinetic energy of 100 j.after traveling a distance 1 m, 19% of initial energy is lost due to air friction .the final speed of body will be?
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