Question

A body of mass o.5 kg start from the rest and cover a distance of 16m in 4s .find the force?

Answer 1

$s = u {t}^{2} + 0.5a {t}^{2}$
s = 16m
t = 4s
u = 0

16 = 0 + 0.5 × a × 4 × 4
16 = a × 8
$a = 2m {s}^{ - 2}$
Force = ma
Force = 0.5×2
Force = 1 N

Answer 2

M=0.5kg

D=16m

T=4s

F=ma

F= 0.5×a

a=d/t^2

a=16÷16

F=0.5×1

F=0.5N