Question

a body of mass root 3 kg is lying on a rough horizontal surface if angle of friction is 30 degree then find net contact force between surfaces ​

Answer 1

Answer:

20

Explanation:

contact force=√(F²+N²)

where F and N are frictional and normal force respectively

also tan α=μ

We get μ=1/√3

F=μmg

=10

N=mg

=10√3

contact force=√400