A body of mass root 3 kg is suspended by a string from a rigid support. The body is pulled horizontally by a force F until the string makes an angle of 30 degree with the vertical. the value of F and tension in the string are
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Hence the tension in the string is 20 N and the force is 10 N.
Explanation:
We are given that:
- Mass of body = 3 Kg
- Horizontal force = F
- Angle = 30°
Solution:
F = T cos (30°)
mg = T sin (30°)
√3 g = T √3 / 2
T = 2 x g = 2 x 10 = 20 N
F = T x 1/2
F = 20 x 1/2 = 10 N
Hence the tension in the string is 20 N and the force is 10 N.
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