Question

A body of volume 100 cm3 is immersed completely in water. calculate the upthrust o the body

Answer 1

According to Archimidies principle
Upthrust force is

Force= weight of displaced water
= mass of displaced water*g
= density of water* volume displaced* g
= 1000* (100 / 100^3) * 9.8
= 9.8/10
= 0.98 newton

Answer 2

Given:

• Volume of body = 100 cm³
• The body is immersed fully in water.

To find:

• Upthrust on the body?

Calculation:

As per Archimedes principle, the upthrust experienced will be equal to the weight of water displaced during immersion.

So, upthrust (buoyant force) will be :

$\boxed{F = volume_{in} \times ( \rho \times g) }$

• So, putting the values in SI UNIT (i.e. density is 1000 kg/m³ , volume will be 10^(-4) m³ and g is 10 m/s²)

$\implies F = {10}^{ - 4} \times ( 1000 \times 10)$

$\implies F = {10}^{ - 4} \times {10}^{4}$

$\implies F = 1 \: N$

So, upthrust experienced by body is 1 Newton.