A body of volume 100 cm3 weighs 5 kgf in air. It is completely immersed in a liquid of density 1.8* 103 kg m-3. Find1 ) the upthrust due to liquid and2 ) the weight of the body in liquid.
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Weight of the body in air is, W = 5 kgf = 5g N
Volume of the body, V = 100 cm3 = 100 × 10-6 = 10-4 m3
Density of the liquid, q = 1.8 × 103 kg/m3
Now,
Upthrust = buoyant force, B = Vqg = 10-4 × 1.8 × 103 × g = 0.18g N = 0.18 kgf
So, weight of the body in liquid = W – B = 5 kgf – 0.18 kgf = 4.82 kgf
Volume of the body, V = 100 cm3 = 100 × 10-6 = 10-4 m3
Density of the liquid, q = 1.8 × 103 kg/m3
Now,
Upthrust = buoyant force, B = Vqg = 10-4 × 1.8 × 103 × g = 0.18g N = 0.18 kgf
So, weight of the body in liquid = W – B = 5 kgf – 0.18 kgf = 4.82 kgf
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Answer by Riya .
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